Part E involves a reaction between the cupric chloride solution and a solution of sodioum phosphate to produce a blue cupric phospate and soduim chloride. This is an example of a double replacement reaction.
3CuCl2 + 2NaPO4 -> Cu3(PO4)2 + 6 NaCl
Measuring out the sodium phosphate!
Here the solid just begins to form between the cupric chloride and sodium phosphate that eventually forms into the cloudy liquid found below.
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